Baseball Display Cubes
Simple surface area question?
A plastic cube it used to display an autographed baseball. The cube has an outer area of 52 square inches.
a. What is the length of an outer edge of the cube?
b. What is the greatest volume the cube can possible have? Explain why the actual volume inside of the cube may be less than the greatest possible volume.
please!!!! 10 points!
LET:
T – TOTAL AREA OF THE CUBE
S – NUMBER OF SIDE OF THE CUBE
E – AREA OF EACH SIDE
L – LENGTH OF EACH SIDES
V – VOLUME OF THE CUBE
T/S=E
52/6=8.6666 SQUARE INCHES
SQUARE ROOT 0F E = L (the square root of the area of the square is the length or width of the square)
SQUARE ROOT OF 8.6666=2.9439 INCHES
ANSWER A
(This question could be interpreted as a question of a single edge or the total of all edges, so I’ll answer both possible question.)
A.1. = 2.9439 INCHES
(THIS IS THE ANSWER IF YOU ARE ASKING ABOUT THE LENGTH OF THE SINGLE EDGE OF THE CUBE)
A.2. = 35.3268 INCHES
(THIS IS THE ANSWER IF YOU ARE ASKING ABOUT THE OVERALL LENGTH OF THE CUBE, YOU HAVE TO MULTIPLY THE SINGLE LENGTH OF THE CUBE BY 12 , BECAUSE CUBE HAVE 12 EDGES.)
L^3=V
2.9439*2.9439*2.9439=25.5134 CUBIC INCHES
ANSWER B. 25.5134 CUBIC INCHES
THE ACTUAL VOLUME (which you refer to the volume inside the cube) OF THE CUBE COULD BE SMALLER DEPENDENT ON THE THICKNESS OF THE WALLS USED TO MAKE THE CUBE THE THICKER IT IS THE SMALLER THE VOLUME INSIDE.
Home Made Baseball Cube Wall Mount Display + Troglodyte!!
